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PreprintarXiv licencearXiv

The Nieuwland number of the Octahedron

Abstract

We prove that the Nieuwland number of the Octahedron is 3√2/4. Along the way, we provide an elementary proof that Rupert's problem for the Octahedron admits no solution in which the outer projection is a hexagon.

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BibTeX
@misc{steininger2026nieuwland,
  title = {{The Nieuwland number of the Octahedron}},
  author = {Jakob Steininger and Sergey Yurkevich},
  howpublished = {arXiv},
  year = {2026},
  month = sep,
  doi = {10.48550/arxiv.2609.10788},
  eprint = {2609.10788},
  archivePrefix = {arXiv},
  url = {https://arxiv.org/abs/2609.10788},
}
RIS
TY  - UNPB
TI  - The Nieuwland number of the Octahedron
AU  - Jakob Steininger
AU  - Sergey Yurkevich
PY  - 2026
DA  - 2026/09/09
PB  - arXiv
DO  - 10.48550/arxiv.2609.10788
UR  - https://arxiv.org/abs/2609.10788
AB  - We prove that the Nieuwland number of the Octahedron is 3√2/4. Along the way, we provide an elementary proof that Rupert's problem for the Octahedron admits no solution in which the outer projection is a hexagon.
ER  -