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Antidirected forests in digraphs

Abstract

A digraph is antidirected if every vertex has indegree zero or outdegree zero. Let k≥2, and let F be an antidirected forest with k arcs and no isolated vertices. We prove that every digraph D of order n with more than gk(n):=2max{binom2k−12, (k−1)(n−k/2)} arcs contains F as a subdigraph. For n≥2k−1, this threshold equals 2ex(n,kK2) and is attained by symmetric digraphs arising from extremal kK2-free graphs. Consequently, the maximum directed extremal number over all such forests is 2ex(n,kK2). The proof combines a counting inequality for rooted antidirected forests, embeddings extending vertex-disjoint arcs, and vertex deletion. In the remaining case, the Gallai--Edmonds decomposition of the underlying graph gives the required bound on the number of arcs.

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BibTeX
@misc{liu2026antidirected,
  title = {{Antidirected forests in digraphs}},
  author = {Gengtao Liu and Yunshu Gao},
  howpublished = {arXiv},
  year = {2026},
  month = sep,
  doi = {10.48550/arxiv.2609.18469},
  eprint = {2609.18469},
  archivePrefix = {arXiv},
  url = {https://arxiv.org/abs/2609.18469},
}
RIS
TY  - UNPB
TI  - Antidirected forests in digraphs
AU  - Gengtao Liu
AU  - Yunshu Gao
PY  - 2026
DA  - 2026/09/16
PB  - arXiv
DO  - 10.48550/arxiv.2609.18469
UR  - https://arxiv.org/abs/2609.18469
AB  - A digraph is antidirected if every vertex has indegree zero or outdegree zero. Let k≥2, and let F be an antidirected forest with k arcs and no isolated vertices. We prove that every digraph D of order n with more than g_k(n):=2max{binom2k−12, (k−1)(n−k/2)} arcs contains F as a subdigraph. For n≥2k−1, this threshold equals 2ex(n,kK_2) and is attained by symmetric digraphs arising from extremal kK_2-free graphs. Consequently, the maximum directed extremal number over all such forests is 2ex(n,kK_2). The proof combines a counting inequality for rooted antidirected forests, embeddings extending vertex-disjoint arcs, and vertex deletion. In the remaining case, the Gallai--Edmonds decomposition of the underlying graph gives the required bound on the number of arcs.
ER  -