Skip to content
DraconiticResearch
Search Sources API
203,203 studies31 sourcesUpdated 8 min ago
PreprintCC BY 4.0arXiv

The fourth generalized Davenport constant of C53

Abstract

For a finite abelian group G and k ≥ 1, the generalized Davenport constant Dk(G) is the least ℓ such that every sequence over G of length at least ℓ has k pairwise disjoint nonempty zero-sum subsequences. A theorem of Freeze and Schmid gives Dk(C53) ≥ 5k+10 for every k ≥ 2. We prove the matching upper bound: D4(C53)=30, and hence Dk(C53)=5k+10 for every k ≥ 2, so the Freeze--Schmid bound is attained by C53 from k=2 onward, as it is by C23 and unlike C33. The proof is finite and computer-assisted. The remaining case reduces to showing that every zero-sum sequence of length $31$ over C53 contains a nonempty zero-sum subsequence of length at most five. A saturation argument confines the multiplicities of a hypothetical counterexample to {1,2,4}, its support pattern to one of $60$ solutions of two linear equations, and its geometry to one of $78$ rank/plane branches normalized to a standard basis; an exhaustive search exhausts every branch with no survivor. The search was carried out by three independently written implementations, and the branch cover was regenerated by separate programs from the lemmas alone; two further machine-verified values, D3(C53)=25 and s≤ 6(C53)=24, enter the second statement, and their records accompany the paper.

Related

  1. The Davenport constant of low-dimensional boxes
    Benjamin Girard, Alain Plagne
    HALPreprintCC BY 4.0Full textAlgebra & number theoryCombinatorics & discrete mathematicsHALarXiv
  2. The small Davenport constant of H27× C3r
    Andreas Volkmann
    arXivPreprintarXiv licenceFull textAlgebra & number theoryCombinatorics & discrete mathematicsarXiv
  3. The Davenport constant of balls and boxes
    Benjamin Girard, Alain Plagne
    HALPreprintCC BY 4.0Full textAlgebra & number theoryCombinatorics & discrete mathematicsHAL
  4. The small Davenport constant of E2× C3r for 0≤ r≤3
    Andreas Volkmann
    arXivPreprintarXiv licenceFull textAlgebra & number theoryCombinatorics & discrete mathematicsarXiv
  5. A twelve-term exclusion for the small Davenport constant of E2× C3r
    Andreas Volkmann
    arXivPreprintarXiv licenceFull textAlgebra & number theoryCombinatorics & discrete mathematicsarXiv
BibTeX
@misc{yiu2026fourth,
  title = {{The fourth generalized Davenport constant of $C_5^3$}},
  author = {Sze Chun Yiu},
  howpublished = {arXiv},
  year = {2026},
  month = sep,
  doi = {10.48550/arxiv.2609.04950},
  eprint = {2609.04950},
  archivePrefix = {arXiv},
  url = {https://arxiv.org/abs/2609.04950},
  note = {CC BY 4.0},
}
RIS
TY  - UNPB
TI  - The fourth generalized Davenport constant of C_5^3
AU  - Sze Chun Yiu
PY  - 2026
DA  - 2026/09/04
PB  - arXiv
DO  - 10.48550/arxiv.2609.04950
UR  - https://arxiv.org/abs/2609.04950
AB  - For a finite abelian group G and k ≥ 1, the generalized Davenport constant D_k(G) is the least ℓ such that every sequence over G of length at least ℓ has k pairwise disjoint nonempty zero-sum subsequences. A theorem of Freeze and Schmid gives D_k(C_5^3) ≥ 5k+10 for every k ≥ 2. We prove the matching upper bound: D_4(C_5^3)=30, and hence D_k(C_5^3)=5k+10 for every k ≥ 2, so the Freeze--Schmid bound is attained by C_5^3 from k=2 onward, as it is by C_2^3 and unlike C_3^3. The proof is finite and computer-assisted. The remaining case reduces to showing that every zero-sum sequence of length $31$ over C_5^3 contains a nonempty zero-sum subsequence of length at most five. A saturation argument confines the multiplicities of a hypothetical counterexample to {1,2,4}, its support pattern to one of $60$ solutions of two linear equations, and its geometry to one of $78$ rank/plane branches normalized to a standard basis; an exhaustive search exhausts every branch with no survivor. The search was carried out by three independently written implementations, and the branch cover was regenerated by separate programs from the lemmas alone; two further machine-verified values, D_3(C_5^3)=25 and s_≤ 6(C_5^3)=24, enter the second statement, and their records accompany the paper.
ER  -