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The Bernoulli property for PSL2ℝ skew products over exponentially mixing base
Abstract
We study the Bernoulli property for skew products of the form f(x,y)=(g(x),A(x)y) on M× PSL2(ℝ)/Γ, where g is a smooth, measure-preserving, exponentially mixing diffeomorphism, Γ<PSL2(ℝ) is a cocompact lattice, and A: M→ PSL2(ℝ) is a C1+α cocycle. We prove that if A has a nonzero Lyapunov exponent, then f is Bernoulli. The proof does not require that f be exponentially mixing. This provides a new method for establishing the Bernoulli property, which applies to a large class of skew products.
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BibTeX
@misc{doucette2026bernoulli,
title = {{The Bernoulli property for $PSL_2\mathbbR$ skew products over exponentially mixing base}},
author = {Meg Doucette},
howpublished = {arXiv},
year = {2026},
month = sep,
doi = {10.48550/arxiv.2609.08017},
eprint = {2609.08017},
archivePrefix = {arXiv},
url = {https://arxiv.org/abs/2609.08017},
}
RIS
TY - UNPB
TI - The Bernoulli property for PSL_2ℝ skew products over exponentially mixing base
AU - Meg Doucette
PY - 2026
DA - 2026/09/07
PB - arXiv
DO - 10.48550/arxiv.2609.08017
UR - https://arxiv.org/abs/2609.08017
AB - We study the Bernoulli property for skew products of the form f(x,y)=(g(x),A(x)y) on M× PSL_2(ℝ)/Γ, where g is a smooth, measure-preserving, exponentially mixing diffeomorphism, Γ<PSL_2(ℝ) is a cocompact lattice, and A: M→ PSL_2(ℝ) is a C^1+α cocycle. We prove that if A has a nonzero Lyapunov exponent, then f is Bernoulli. The proof does not require that f be exponentially mixing. This provides a new method for establishing the Bernoulli property, which applies to a large class of skew products.
ER -