Skip to content
DraconiticResearch
Search Sources API
201,818 studies31 sourcesUpdated 51 min ago
PreprintarXiv licencearXiv

On the probability that a random Latin square is all-even

Abstract

In a Latin square, every row can be interpreted as a permutation, and therefore has a parity (even or odd). We prove that in a uniformly random n× n Latin square, the probability that all rows are even is of the form 2−n+o(n). This fills a gap left by recent work of Kwan, Petrova and Sawhney: they proved that the row parities behave like a sequence of independent coin flips in a variety of different senses, but they were not able to lower-bound the all-even probability, as their approach had a small number of "exceptional rows" whose parities they could not control. In fact, we prove a more general theorem on the probability of any possible prescription of row parities, column parities and symbol parities. Our approach extends the ideas of Kwan, Petrova and Sawhney, introducing a new way to "bootstrap" intercalate switchings to control more complex switching operations.

Related

  1. Avoiding a partial Latin square with an isotope of a given Latin square
    Stijn Cambie, Ian M. Wanless
    arXivPreprintCC BY 4.0Full textCombinatorics & discrete mathematicsarXiv
  2. Counting transversals in Latin squares over groups of even order
    James A. Davis, Jonathan Jedwab, Ian M. Wanless +1
    arXivPreprintCC BY 4.0Full textCombinatorics & discrete mathematicsarXiv
  3. A counting proof for the smallest critical set in a Latin square
    Richard Bean
    arXivPreprintCC BY 4.0Full textCombinatorics & discrete mathematicsarXiv
  4. A nearly tight bound on the probability G(n,p) is even-degenerate
    Ting-Wei Chao, Bruce Reed
    arXivPreprintCC BY-NC-SA 4.0Full textCombinatorics & discrete mathematicsarXiv
  5. An Exact Strip Observable and the Half-Plane One-Arm Probability for Critical Bond Percolation on the Square Lattice
    Wang Zhou
    arXivPreprintarXiv licenceFull textProbabilityarXiv
BibTeX
@misc{greenhill2026probability,
  title = {{On the probability that a random Latin square is all-even}},
  author = {Catherine Greenhill and Lenka Kopfová and Matthew Kwan and Kalina Petrova},
  howpublished = {arXiv},
  year = {2026},
  month = oct,
  doi = {10.48550/arxiv.2610.13487},
  eprint = {2610.13487},
  archivePrefix = {arXiv},
  url = {https://arxiv.org/abs/2610.13487},
}
RIS
TY  - UNPB
TI  - On the probability that a random Latin square is all-even
AU  - Catherine Greenhill
AU  - Lenka Kopfová
AU  - Matthew Kwan
AU  - Kalina Petrova
PY  - 2026
DA  - 2026/10/09
PB  - arXiv
DO  - 10.48550/arxiv.2610.13487
UR  - https://arxiv.org/abs/2610.13487
AB  - In a Latin square, every row can be interpreted as a permutation, and therefore has a parity (even or odd). We prove that in a uniformly random n× n Latin square, the probability that all rows are even is of the form 2^−n+o(n). This fills a gap left by recent work of Kwan, Petrova and Sawhney: they proved that the row parities behave like a sequence of independent coin flips in a variety of different senses, but they were not able to lower-bound the all-even probability, as their approach had a small number of "exceptional rows" whose parities they could not control. In fact, we prove a more general theorem on the probability of any possible prescription of row parities, column parities and symbol parities. Our approach extends the ideas of Kwan, Petrova and Sawhney, introducing a new way to "bootstrap" intercalate switchings to control more complex switching operations.
ER  -