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Cube-freeness and a square formula for canonical trace ideals of Stanley--Reisner rings
Abstract
Let I be a monomial ideal in S=k[x1,…,xn], and set R=S/I. We prove that if I is a-bounded and M is a positively b-determined R-module, then trR(M) is (a+b)-bounded. For the canonical module, this gives the bound 2a. In particular, the canonical trace ideal of every Stanley--Reisner ring is a cube-free monomial ideal. We also prove that, for a Stanley--Reisner ring satisfying (S2), the canonical trace ideal is the square of its radical if and only if the ring satisfies (G2).
Related
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- Characterization of Stanley-Reisner varieties by their automorphism group
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BibTeX
@misc{miyashita2026cubefreeness,
title = {{Cube-freeness and a square formula for canonical trace ideals of Stanley--Reisner rings}},
author = {Sora Miyashita},
howpublished = {arXiv},
year = {2026},
month = nov,
doi = {10.48550/arxiv.2611.00714},
eprint = {2611.00714},
archivePrefix = {arXiv},
url = {https://arxiv.org/abs/2611.00714},
}
RIS
TY - UNPB
TI - Cube-freeness and a square formula for canonical trace ideals of Stanley--Reisner rings
AU - Sora Miyashita
PY - 2026
DA - 2026/11/01
PB - arXiv
DO - 10.48550/arxiv.2611.00714
UR - https://arxiv.org/abs/2611.00714
AB - Let I be a monomial ideal in S=k[x_1,…,x_n], and set R=S/I. We prove that if I is a-bounded and M is a positively b-determined R-module, then tr_R(M) is (a+b)-bounded. For the canonical module, this gives the bound 2a. In particular, the canonical trace ideal of every Stanley--Reisner ring is a cube-free monomial ideal. We also prove that, for a Stanley--Reisner ring satisfying (S_2), the canonical trace ideal is the square of its radical if and only if the ring satisfies (G_2).
ER -