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PreprintCC BY 4.0arXiv

Fanout Complexity of Symmetric Boolean Functions in QAC0

Abstract

Whether QAC0 can compute PARITYn remains open. Computing PARITYn is equivalent to implementing FANOUTn under QAC0 reductions. This raises a more general question: for an arbitrary symmetric Boolean function f:{0,1}n→{0,1}, what fanout size is necessary and sufficient for computing f in QAC0? We show that the answer is exactly the transition radius ρ(f): computing f and implementing FANOUTρ(f) are equivalent under QAC0 reductions. In particular, if ρ(f)≥ nδ for some constant δ>0, then computing f is QAC0f-complete. Combined with Paturi's theorem, our characterization implies that if PARITYn ∉ QAC0, then any Boolean function in QAC0 of approximate degree n1/2+Ω(1) must be nonsymmetric.

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BibTeX
@misc{xu2026fanout,
  title = {{Fanout Complexity of Symmetric Boolean Functions in $\mathsfQAC^0$}},
  author = {Boyan Xu and Lvzhou Li},
  howpublished = {arXiv},
  year = {2026},
  month = sep,
  doi = {10.48550/arxiv.2609.05153},
  eprint = {2609.05153},
  archivePrefix = {arXiv},
  url = {https://arxiv.org/abs/2609.05153},
  note = {CC BY 4.0},
}
RIS
TY  - UNPB
TI  - Fanout Complexity of Symmetric Boolean Functions in QAC^0
AU  - Boyan Xu
AU  - Lvzhou Li
PY  - 2026
DA  - 2026/09/04
PB  - arXiv
DO  - 10.48550/arxiv.2609.05153
UR  - https://arxiv.org/abs/2609.05153
AB  - Whether QAC^0 can compute PARITY_n remains open. Computing PARITY_n is equivalent to implementing FANOUT_n under QAC^0 reductions. This raises a more general question: for an arbitrary symmetric Boolean function f:{0,1}^n→{0,1}, what fanout size is necessary and sufficient for computing f in QAC^0? We show that the answer is exactly the transition radius ρ(f): computing f and implementing FANOUT_ρ(f) are equivalent under QAC^0 reductions. In particular, if ρ(f)≥ n^δ for some constant δ>0, then computing f is QAC^0_f-complete. Combined with Paturi's theorem, our characterization implies that if PARITY_n ∉ QAC^0, then any Boolean function in QAC^0 of approximate degree n^1/2+Ω(1) must be nonsymmetric.
ER  -