PreprintCC BY 4.0arXiv
Countable compactness is A-invariant
Abstract
Let A(X) denote the free Abelian topological group over a Tychonoff space X. We prove that if A(X) and A(Y) are topologically isomorphic and X is countably compact, then Y is also countably compact. Thus countable compactness is an A-invariant and, consequently, an M-invariant; this answers Open Problem~7.10.1 of Arhangel'skii and Tkachenko.
Related
BibTeX
@misc{huang2026countable,
title = {{Countable compactness is $A$-invariant}},
author = {ZhouXiang Huang},
howpublished = {arXiv},
year = {2026},
month = oct,
doi = {10.48550/arxiv.2610.12131},
eprint = {2610.12131},
archivePrefix = {arXiv},
url = {https://arxiv.org/abs/2610.12131},
note = {CC BY 4.0},
}
RIS
TY - UNPB
TI - Countable compactness is A-invariant
AU - ZhouXiang Huang
PY - 2026
DA - 2026/10/08
PB - arXiv
DO - 10.48550/arxiv.2610.12131
UR - https://arxiv.org/abs/2610.12131
AB - Let A(X) denote the free Abelian topological group over a Tychonoff space X. We prove that if A(X) and A(Y) are topologically isomorphic and X is countably compact, then Y is also countably compact. Thus countable compactness is an A-invariant and, consequently, an M-invariant; this answers Open Problem~7.10.1 of Arhangel'skii and Tkachenko.
ER -