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Separating hash families with large universe II

Abstract

For fixed integers t,k≥ 2, put N=(t−1)(k−1)+1. We prove that the maximum universe size of a t-perfect hash family of length N over an alphabet of size q satisfies $ p_t(N,q)\ge q^{k-o(1)}$. Together with monotonicity in the length, this gives a positive answer to a question of Blackburn, Etzion, Stinson and Zaverucha for every choice of feasible parameters. Our proof combines the Nash--Williams--Tutte theorem, a graph-theoretic elimination argument, and a solution-free-set theorem established in our previous work.

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BibTeX
@misc{wei2026separating,
  title = {{Separating hash families with large universe II}},
  author = {Xin Wei and Gennian Ge},
  howpublished = {arXiv},
  year = {2026},
  month = oct,
  doi = {10.48550/arxiv.2610.41353},
  eprint = {2610.41353},
  archivePrefix = {arXiv},
  url = {https://arxiv.org/abs/2610.41353},
}
RIS
TY  - UNPB
TI  - Separating hash families with large universe II
AU  - Xin Wei
AU  - Gennian Ge
PY  - 2026
DA  - 2026/10/30
PB  - arXiv
DO  - 10.48550/arxiv.2610.41353
UR  - https://arxiv.org/abs/2610.41353
AB  - For fixed integers t,k≥ 2, put N=(t−1)(k−1)+1. We prove that the maximum universe size of a t-perfect hash family of length N over an alphabet of size q satisfies $ p_t(N,q)\ge q^{k-o(1)}$. Together with monotonicity in the length, this gives a positive answer to a question of Blackburn, Etzion, Stinson and Zaverucha for every choice of feasible parameters. Our proof combines the Nash--Williams--Tutte theorem, a graph-theoretic elimination argument, and a solution-free-set theorem established in our previous work.
ER  -