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PreprintCC BY 4.0arXiv

Making Every Number from 1 to N Under a Fixed Cycle of +, ×, −, ÷

Abstract

Start with the number $2$. At each move, combine two numbers already made, but the operations must be used in the fixed repeating order +,×,−,÷. We ask for the fewest moves needed to make every integer from $1$ to N. Since $2$ is already one of the numbers we want and each move makes at most one new number, at least N−1 moves are needed. We show that N−1 moves are also enough for every N≥ 9. Conventional induction cannot work, because a division that comes right after a completed interval {1,…,P} produces numbers already made. Instead we extend a completed interval {1,…,P} to {1,…,3P} all at once, which counting shows is the smallest multiplicative extension P→ kP that can work, and then adjust the last few moves to reach every other N. For 9≤ N≤ 33 we give explicit sequences, found by computer search.

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BibTeX
@misc{lesmana2026making,
  title = {{Making Every Number from 1 to N Under a Fixed Cycle of $+$, $\times$, $-$, $÷$}},
  author = {Sean Lesmana and Theodore Tjugiarto},
  howpublished = {arXiv},
  year = {2026},
  month = oct,
  doi = {10.48550/arxiv.2610.10095},
  eprint = {2610.10095},
  archivePrefix = {arXiv},
  url = {https://arxiv.org/abs/2610.10095},
  note = {CC BY 4.0},
}
RIS
TY  - UNPB
TI  - Making Every Number from 1 to N Under a Fixed Cycle of +, ×, −, ÷
AU  - Sean Lesmana
AU  - Theodore Tjugiarto
PY  - 2026
DA  - 2026/10/07
PB  - arXiv
DO  - 10.48550/arxiv.2610.10095
UR  - https://arxiv.org/abs/2610.10095
AB  - Start with the number $2$. At each move, combine two numbers already made, but the operations must be used in the fixed repeating order +,×,−,÷. We ask for the fewest moves needed to make every integer from $1$ to N. Since $2$ is already one of the numbers we want and each move makes at most one new number, at least N−1 moves are needed. We show that N−1 moves are also enough for every N≥ 9. Conventional induction cannot work, because a division that comes right after a completed interval {1,…,P} produces numbers already made. Instead we extend a completed interval {1,…,P} to {1,…,3P} all at once, which counting shows is the smallest multiplicative extension P→ kP that can work, and then adjust the last few moves to reach every other N. For 9≤ N≤ 33 we give explicit sequences, found by computer search.
ER  -