PreprintCC BY 4.0arXiv
On Bayart's unique factorization problem
Abstract
Let A be a ring such that the formal power series ring A[[t]] is a unique factorization domain. Bayart's problem asks whether the formal power series ring in two variables A[[x,t]] must also be a UFD. Equivalently, is every irreducible element f∈ A[[x,t]] prime? We prove that the answer is yes whenever the constant term of f is an associate of pm, for any prime p ∈ A and 1≤ m≤3, and for m=4 if A contains Q. We also prove the following reduction: To prove a positive answer to Bayart's problem, it suffices to prove that $A[x][[t]]$ is a UFD whenever A[[t]] is.
Related
- Bouvier's Conjecture and Dimension Sequences of Unique Factorization Domains
- Unique factorization results for generalized power series
- Unique Factorization of Power Series Rings over Q-UFDs of Dimension at Most 3
- The unique predual problem for Lipschitz spaces, revisited
- Sharp Probabilistic Normwise Backward Error Bounds for LU Factorization
BibTeX
@misc{paran2026bayarts,
title = {{On Bayart's unique factorization problem}},
author = {Elad Paran},
howpublished = {arXiv},
year = {2026},
month = nov,
doi = {10.48550/arxiv.2611.01622},
eprint = {2611.01622},
archivePrefix = {arXiv},
url = {https://arxiv.org/abs/2611.01622},
note = {CC BY 4.0},
}
RIS
TY - UNPB
TI - On Bayart's unique factorization problem
AU - Elad Paran
PY - 2026
DA - 2026/11/01
PB - arXiv
DO - 10.48550/arxiv.2611.01622
UR - https://arxiv.org/abs/2611.01622
AB - Let A be a ring such that the formal power series ring A[[t]] is a unique factorization domain. Bayart's problem asks whether the formal power series ring in two variables A[[x,t]] must also be a UFD. Equivalently, is every irreducible element f∈ A[[x,t]] prime? We prove that the answer is yes whenever the constant term of f is an associate of p^m, for any prime p ∈ A and 1≤ m≤3, and for m=4 if A contains Q. We also prove the following reduction: To prove a positive answer to Bayart's problem, it suffices to prove that $A[x][[t]]$ is a UFD whenever A[[t]] is.
ER -