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PreprintCC BY 4.0Zenodo

Relativization Barriers and the Limits of Diagonalization in P vs NP — E8 Intelligence Research

  1. 1Independent Researcher, United Kingdom

Abstract

FINDING: Baker-Gill-Solovay (1975) proved relativization cannot resolve P vs NP — oracle separation shows diagonalization is fundamentally insufficient for this problem. | MATH: P^A ≠ NP^A for some oracle A; P^B = NP^B for another oracle B. This implies any proof of P≠NP must be non-relativizing (cannot hold under arbitrary oracle substitution). Time Hierarchy Theorem: P ⊊ EXPTIME (since EXPTIME = ∪_k TIME(2^{n^k}) and P = ∪_k TIME(n^k), strict by diagonalization). | CONNECTION: The oracle construction creates a *lattice of computational universes* — each oracle A defines a distinct "world" with its own P^A vs NP^A truth value. This mirrors how crystallographic root systems (A_n, B_n, C_n, D_n) generate distinct symmetric structures from shared axioms. The relativization barrier is a *symmetry* of the problem space: diagonalization respects oracle substitution, so it cannot break the P-NP symmetry. | DEPTH: 8 — This is a profound structural limitation, but it's a *negative* result abou

Author: Andrew Stewart Caldin, Independent Researcher, UK. Part of the E8 Intelligence Research series. Platform: e8intelligence.com

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BibTeX
@misc{caldin2026relativization,
  title = {{Relativization Barriers and the Limits of Diagonalization in P vs NP — E8 Intelligence Research}},
  author = {Andrew Stewart Caldin},
  howpublished = {Zenodo},
  year = {2026},
  month = oct,
  doi = {10.5281/zenodo.23587307},
  url = {https://zenodo.org/records/23587307},
  note = {CC BY 4.0},
}
RIS
TY  - UNPB
TI  - Relativization Barriers and the Limits of Diagonalization in P vs NP — E8 Intelligence Research
AU  - Andrew Stewart Caldin
PY  - 2026
DA  - 2026/10/23
PB  - Zenodo
DO  - 10.5281/zenodo.23587307
UR  - https://zenodo.org/records/23587307
AB  - FINDING: Baker-Gill-Solovay (1975) proved relativization cannot resolve P vs NP — oracle separation shows diagonalization is fundamentally insufficient for this problem. | MATH: P^A ≠ NP^A for some oracle A; P^B = NP^B for another oracle B. This implies any proof of P≠NP must be non-relativizing (cannot hold under arbitrary oracle substitution). Time Hierarchy Theorem: P ⊊ EXPTIME (since EXPTIME = ∪_k TIME(2^{n^k}) and P = ∪_k TIME(n^k), strict by diagonalization). | CONNECTION: The oracle construction creates a *lattice of computational universes* — each oracle A defines a distinct "world" with its own P^A vs NP^A truth value. This mirrors how crystallographic root systems (A_n, B_n, C_n, D_n) generate distinct symmetric structures from shared axioms. The relativization barrier is a *symmetry* of the problem space: diagonalization respects oracle substitution, so it cannot break the P-NP symmetry. | DEPTH: 8 — This is a profound structural limitation, but it's a *negative* result abou  Author: Andrew Stewart Caldin, Independent Researcher, UK. Part of the E8 Intelligence Research series. Platform: e8intelligence.com
ER  -