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PreprintCC BY 4.0Zenodo

Diagonalization Proves More Time Solves More Problems — E8 Intelligence Research

  1. 1Independent Researcher, United Kingdom

Abstract

FINDING: The Time Hierarchy Theorem proves that more time strictly enables more computational problems, via diagonalization — a constructive self-reference argument that separates complexity classes. | MATH: For time-constructible f(n) > g(n) log g(n), DTIME(g(n)) subsetneq DTIME(f(n)). Proof diagonalizes: simulate all machines of time g(n) on input x, flip the output of machine Mx if it halts within g(|x|), else accept. The separating language is in DTIME(f(n)) but not in DTIME(g(n)). Key constants: the log factor arises from simulation overhead — the universal machine's tape indexing costs O(log t) per step. | CONNECTION: The diagonalization step is a binary complement — a reflection symmetry across the diagonal of the time-indexed machine table. This is structurally analogous to the 0.618/0.382 golden ratio split in that it creates a *gap* that cannot be bridged by the lower class — the gap ratio here is not

Author: Andrew Stewart Caldin, Independent Researcher, UK. Part of the E8 Intelligence Research series. Platform: e8intelligence.com

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BibTeX
@misc{caldin2026diagonalization,
  title = {{Diagonalization Proves More Time Solves More Problems — E8 Intelligence Research}},
  author = {Andrew Stewart Caldin},
  howpublished = {Zenodo},
  year = {2026},
  month = oct,
  doi = {10.5281/zenodo.23553837},
  url = {https://zenodo.org/records/23553837},
  note = {CC BY 4.0},
}
RIS
TY  - UNPB
TI  - Diagonalization Proves More Time Solves More Problems — E8 Intelligence Research
AU  - Andrew Stewart Caldin
PY  - 2026
DA  - 2026/10/22
PB  - Zenodo
DO  - 10.5281/zenodo.23553837
UR  - https://zenodo.org/records/23553837
AB  - FINDING: The Time Hierarchy Theorem proves that more time strictly enables more computational problems, via diagonalization — a constructive self-reference argument that separates complexity classes. | MATH: For time-constructible f(n) > g(n) log g(n), DTIME(g(n)) subsetneq DTIME(f(n)). Proof diagonalizes: simulate all machines of time g(n) on input x, flip the output of machine M_x if it halts within g(|x|), else accept. The separating language is in DTIME(f(n)) but not in DTIME(g(n)). Key constants: the log factor arises from simulation overhead — the universal machine's tape indexing costs O(log t) per step. | CONNECTION: The diagonalization step is a binary complement — a reflection symmetry across the diagonal of the time-indexed machine table. This is structurally analogous to the 0.618/0.382 golden ratio split in that it creates a *gap* that cannot be bridged by the lower class — the gap ratio here is not  Author: Andrew Stewart Caldin, Independent Researcher, UK. Part of the E8 Intelligence Research series. Platform: e8intelligence.com
ER  -